Loading XML with webclient to use as style for datagrid

2 replies. Latest Post by Amanda Wang - MSFT on July 7, 2009.

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Jya

Member

0 points

4 Posts

Loading XML with webclient to use as style for datagrid

07-03-2009 5:12 AM |

I have an XML-file which contains a style and is located under the Clientbin-directory.

The xml-file is downloaded as followed.

var webClient = new WebClient();
webClient.DownloadStringCompleted += new DownloadStringCompletedEventHandler(webClient_DownloadStringCompleted);
webClient.DownloadStringAsync(new Uri("DatagridRowStyle.xml", UriKind.RelativeOrAbsolute));

After this i convert my result to a style as followed

string XmlString = e.Result;
XElement elem = XElement.Load(XmlReader.Create(new StringReader(XmlString)));
s = System.Windows.Markup.XamlReader.Load((elem).ToString()) as Style;

but when I assign this style to my datagrid it gives me an error  "xamlparseexception occured" at line 0, position 0

After this I tried exactly the same with a regular button and gave it this style and this works

<Style xmlns="http://schemas.microsoft.com/winfx/2006/xaml/presentation"
       xmlns:x="http://schemas.microsoft.com/winfx/2006/xaml"
       x:Key="btnTest"
       TargetType="Button">  
  <Setter Property="Background" Value="Red"/>
  <Setter Property="FontSize" Value="25"/>
  <Setter Property="Foreground" Value="Blue"/>
</Style>

 can someone tell me what i'm doing wrong?

Thanks

codebased

Participant

806 points

360 Posts

Re: Loading XML with webclient to use as style for datagrid

07-04-2009 5:28 AM |

Do you have this in the project already and registered with the same namespace?

xmlns:datagrid="clr-namespace:System.Windows.Controls;assembly=System.Windows.Controls.Data"

"If I've answered your query then please mark it as "Answered".

Amanda W...

All-Star

17234 points

1,466 Posts

Re: Loading XML with webclient to use as style for datagrid

07-07-2009 6:07 AM |

Hi,

Jya:
can someone tell me what i'm doing wrong?

The cause of your problem is on the line code XElement elem = XElement.Load(XmlReader.Create(new StringReader(XmlString)));

You can try to set a break point on this line code, you will notice elem content includes the content of the xml and the attributes' values, in other word the elem does not have the correct xml format conent. That's why the XamlReader.Load does not the parse the xml correctly.

You can try to refer below code, use XDocument instead of XElement:

void webClient_DownloadStringCompleted(object sender, DownloadStringCompletedEventArgs e)
        {
            string XmlString = e.Result;

            XDocument doc = XDocument.Load(new StringReader(XmlString));

         //   XElement elem = XElement.Load(XmlReader.Create(new StringReader(XmlString)));
          // XElement elem = XElement.Load(XmlReader.Create(XmlString)));
          Style s = System.Windows.Markup.XamlReader.Load((doc).ToString()) as Style;
        }

Amanda Wang
Microsoft Online Community Support

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