How to show XAML file as model dialog?

5 replies. Latest Post by Keith.Mahoney on July 15, 2008.

(0)

Member

17 points

How to show XAML file as model dialog?

07-14-2008 2:44 AM |

Hi, I have 3 XAML files in my project. When I click on button I want to show XAML file as model dialog. How can I do that. Any help would be appreciated.

Thanks

mustafac...

Member

36 points

39 Posts

Re: How to show XAML file as model dialog?

07-14-2008 3:23 AM |

Hi;

you can use this methot

MySoftClass=projectName

path = "MySoftClass.ResourceTemplates.xaml";

or

path =""MySoftClass.Generic.xaml";

public MyContollSoft(String Path)

{

Assembly assembly = Assembly.GetExecutingAssembly();
// string fooResourceName = "MySoftClass.generic.xaml"; you can read like this
string fooResourceName = Path;
using (Stream s = assembly.GetManifestResourceStream(fooResourceName))
{
StreamReader reader = new StreamReader(s);
string xaml = reader.ReadToEnd();
ResourceDictionary rdd = (ResourceDictionary)XamlReader.Load(xaml);
Style myStyle = rdd["myStyle"] as Style;
if (myStyle != null)
{
this.Style = myStyle;
}
reader.Close();
s.Close();
}
DefaultStyleKey = typeof(MyContollSoft);
}

pmkr

Member

17 points

31 Posts

Re: How to show XAML file as model dialog?

07-14-2008 7:00 AM |

Hi Thanks for your reply. I couldn't understand this code. Could you please explain this?. What is this MySoftClass=projectName meaning. and there is not intellisense for assembly. How can I get this Assembly abject?

Thanks

mustafac...

Member

36 points

39 Posts

Re: How to show XAML file as model dialog?

07-15-2008 10:20 AM |

you can get Assembly name

Assembly assembly = Assembly.GetExecutingAssembly();

            // Retrieve a list of resource names contained by the assembly.
            string[] resourceNames = assembly.GetManifestResourceNames();
            foreach (string resourceName in resourceNames)
            {
                Console.WriteLine(resourceName);
            }

sladapter

All-Star

20775 points

3,818 Posts

Re: How to show XAML file as model dialog?

07-15-2008 10:59 AM |

There is no Modal Dialog in Sivlerlight. But you can simulate one by putting your UserControl to a Canvas and make this Canvas on top of everything on your page. Between your top Canvas and the rest of the page you put a simi-transparent rectangle to mask the rest of the page. So no user input is accepted in the main page until you close your Top canvas (make it visibility=Collapsed).

Take a look at this Scott Gu's tutorial. It shows you how to display a detailed section data in a "Modal" box: http://weblogs.asp.net/scottgu/archive/2008/02/22/first-look-at-silverlight-2.aspx

If you want that box be able to be draggable, take a look that this code I put together. It's a resizable and draggble popup window you can put any content in it. You can also make it "Modal". You can download the code.

http://silverlight.net/forums/p/12467/41324.aspx#41324

sladapter
Software Engineer
Aprimo, Inc

Please remember to mark the replies as answers if they answered your question

Keith.Ma...

Participant

872 points

131 Posts

Re: How to show XAML file as model dialog?

07-15-2008 5:32 PM |

Hi pmkr,
I assume that the three xaml files are UserControls in your project?
The easiest way to get modal-dialog-like behaviour is Silverlight is to place your UserControl into a PopUp control.

The following links should be helpful
http://msdn.microsoft.com/en-us/library/system.windows.controls.primitives.popup(VS.95).aspx
http://blogs.msdn.com/silverlight_sdk/archive/2008/04/18/playing-with-the-popup-control.aspx

Keith Mahoney
Silverlight SDET
Microsoft

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